Example: Optimal Design¶
Problem Description¶
A chemist is trying to improve the yield of a chemical process.
She can vary:
- Reaction time (40-50 minutes)
- Temperature (80-90 °C)
With one output, or response, variable:
- Conversion (%)
Design Choice¶
Due to the expense of the experiment, only 6 runs may be performed. From prior experimention the chemist knows to expect a quadratic effect. Standard designs such as a two-level factorial (with center points), or a Central Composite design have too many runs. Instead the chemist decides to use an optimal design, where the factor settings are chosen in an algorithmic search, designed to optimize some criteria. We will be using the D-optimal criteria, which minimizes the joint confidence interval of the model parameters.
This can easily be done in dexpy using
build_optimal
. Note that by default the
size of the design is the minimal number of runs required to support the model
(in this case 6).
import dexpy.optimal
from dexpy.model import ModelOrder
reaction_design = dexpy.optimal.build_optimal(2, order=ModelOrder.quadratic)
column_names = ['time', 'temp']
actual_lows = { 'time': 40, 'temp': 80 }
actual_highs = { 'time': 50, 'temp': 90 }
reaction_design.columns = column_names
print(coded_to_actual(reaction_design, actual_lows, actual_highs))
time | temp | |
0 | 43.64 | 80.00 |
1 | 40.00 | 90.00 |
2 | 40.00 | 82.73 |
3 | 50.00 | 80.00 |
4 | 45.45 | 85.45 |
5 | 50.00 | 90.00 |
As you can see, the runs are arranged in a less structured manner than a standard design. If you look at the design graphically, you can see that the points are spread out throughout the space.
import seaborn as sns
fg = sns.lmplot('time', 'temp', data=reaction_design, fit_reg=False)
ax = fg.axes[0, 0]
ax.set_xticks([-1, 0, 1])
ax.set_xticklabels(['40 min', '45 min', '50 min'])
ax.set_yticks([-1, 0, 1])
ax.set_yticklabels(['80C', '85C', '90C'])
sns.plt.show()
We can calculate the D-optimality of this design, which is just the determinant of the information matrix \(|X'X|\).
from dexpy.model import make_model, ModelOrder
from patsy import dmatrix
import numpy as np
quad_model = make_model(reaction_design.columns, ModelOrder.quadratic)
X = dmatrix(quad_model, reaction_design)
XtX = np.dot(np.transpose(X), X)
d = np.linalg.det(XtX)
print("|(X'X)| for optimal design: {}".format(d))
# |(X'X)| for optimal design: 264.56712477125734
What if the chemist was able to run 10 experiments? You can give the optimal builder a run_count parameter.
import dexpy.optimal
from dexpy.model import ModelOrder
reaction_design = dexpy.optimal.build_optimal(2, run_count=10, order=ModelOrder.quadratic)
column_names = ['time', 'temp']
actual_lows = { 'time': 40, 'temp': 80 }
actual_highs = { 'time': 50, 'temp': 90 }
reaction_design.columns = column_names
print(coded_to_actual(reaction_design, actual_lows, actual_highs))
time | temp | |
0 | 50.0 | 80.0 |
1 | 50.0 | 85.5 |
2 | 40.0 | 90.0 |
3 | 50.0 | 90.0 |
4 | 40.0 | 80.0 |
5 | 40.0 | 85.5 |
6 | 50.0 | 80.0 |
7 | 44.5 | 80.0 |
8 | 45.4 | 84.5 |
9 | 44.5 | 90.0 |
Notice that there appears to be only 9 runs in the image. That is because one of the vertices (indicated in red) has been duplicated by the optimal search algorithm. Both run 0 and run 6 have a time of 50 minutes and a temp of 80 °C.
Note that the run_count parameter must be greater than, or equal to, the size of the model. In this example, the quadratic model \(\hat{y} = 1 + X_1 + X_2 + {X_1}{X_2} + X_1^2 + X_2^2\) requires at least 6 runs. If you try to pass in too few runs you get an exception.
import dexpy.optimal
from dexpy.model import ModelOrder
reaction_design = dexpy.optimal.build_optimal(2, run_count=4, order=ModelOrder.quadratic)
Produces:
ValueError: Can't build a design of size 4 for a model of rank 6. Model: '(X1+X2)**2+pow(X1,2)+pow(X2, 2)'